Question

(49)^3/2-(49)^5/2/49

Answer 1

as 49 can be written as 7^2
therefore
(7^2)^3/2 - ((7^2)^5/2) ÷ 7^2
7^3-7^5/7^2
7^3 - 7^(5-2)
7^3 - 7^3
0

Answer 2

The value of given expression is 0.

Step-by-step explanation:

Consider the given expression is

$(49)^{\frac{3}{2}}-\dfrac{49^{\frac{5}{2}}}{49}$

In the above expression 49 can be written as $7^2$.

$(7^2)^{\frac{3}{2}}-\dfrac{(7^2)^{\frac{5}{2}}}{7^2}$

Using the properties of exponents we get

$7^3-\dfrac{7^5}{7^2}$           $[\because (a^m)^n=a^{mn}]$

$7^3-7^{5-2}$          $[\because \dfrac{a^m}{a^n}=a^{m-n}]$

$7^3-7^{3}$

$0$

Therefore value of given expression is 0.

#Learn more

Simplify and express the result with positive exponents.

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