Question

(49÷36) raised to 2 bracket raised to 1/3 brcket raised to 6

Answer 1

$( {( {( { \frac{49}{36} )}^{2} )}^{ \frac{1}{3} } })^{6} \\ { (\frac{49}{36}) }^{4} \\ {( \frac{7}{6}) }^{8}$

since

$( { ({ {x}^{a} })^{b} })^{c} = {x}^{abc}$

hope it helps.