Question

49^(7n-8)=7^3, find value of n.

Answer 1

Answer:

$n=\dfrac{19}{14}$

Step-by-step explanation:

$49^{(7n-8)}=7^3\\\\(7^2)^{(7n-8)}=7^3\\\\7^{2{(7n-8)}}=7^3\\\\2(7n-8)=3\\\\n=\dfrac{19}{14}$