49
9. If 3 cos 0 = 5 sin e, then the value of
5 sin 0-2 sec 0 + 2 cos 0
is
5 sin 0 +2 sec 0 - 2 cos 0
271
316
542
(a)
(b)
979
2937
(c)
(d) None of these
2937
2
a
Answers
Answered by
2
Answer:
hi, thanks for asking the ques
Explanation:
3cosθ=5sinθ
cosθ=(
3
5
)sinθ
cos
2
θ=(
3
5
)
2
sin
2
θ
1−sin
2
θ=(
9
25
)sin
2
θ
⇒sin
2
θ=
34
9
∴sinθ=
34
3
cos
2
θ=1−sin
2
θ=1−
34
9
=
34
25
∴cosθ=
34
5
∴
5sinθ−2sec
3
θ+2cosθ
5sinθ−2sec
3
θ+2cosθ
=
5×
34
3
−2×
125
34
34
+2×
34
5
5×
34
3
−2×
125
34
34
+2×
34
5
=
34
15
−2×
125
34
34
+
34
10
34
15
−2×
125
34
34
+
34
10
=
34
25
−2×
125
34
34
34
25
−2×
125
34
34
=1
hope this helps u out
#PlzMarkBrainliest
Answered by
0
Answer:
mine is coming this ....you can take some help....hope my answer is correct and will be able to help you...the answer according to me is coming d part...thanks
Attachments:
Similar questions