Question

49.
A sphere of radius 10 cm is given a charge of
20 u C on its surface. The charge density of the
sphere
is
58.
a) 3.185 x 10-6 C/m2 b) 2 x 10-6 C/m²
c) 3 x 10° C/m? d) 1.59 x 10-4 C/m²​

Answer 1

Answer:

2/691;010,-0+0+¥+9×90#¥#000789♤0<8

Answer 2

Answer:

Electric field intensity (E) at a distance (d) from the centre of a sphere containing net charge q is given by the relation,

E= q/4π∈down0d²

Where,

q= Net charge = 1.5×10 /3 N/C

d= =20cm=0.2m

And,

1/4π∈down0 = 9×10^9 Nm

2

C

−2

∴q=E(4π∈0)d²

= 1.5×10³×(0.2)2/9×10^9

=6.67×10^9C

=6.67nC.

Because the electric field lines point radially inwards, the charge on the sphere is negative. Therefore, the net charge on the sphere is 6.67 nC