Question

49. Express 145.6 L of chlorine in terms of gram moles.
(a) 6.5 g moles (b) 4.5 g moles
(c) 0.65 g moles (d).9.5 g moles
​

Answer 1

hope I had resolved your query Kindly go through solution and like and follow me

Answer 2

Given,

The volume of chlorine = 145.6 L

At STP conditions, 1 g mole of gas = 22.4 L

That is 1 L of gas = $\frac{1}{22.4}$ g mole of gas.

Therefore, 145.6 L of chlorine = ($\frac{1}{22.4}$×145.6) g moles

                                                 = 6.5 g moles