Question

49 grams of H2SO4 are dissolved in enough water to make it 1 litre of solutions of density 1.049 g/cc. Find the molarity,normality,molality of H2SO4 in the solution.

Answer 1

Explanation:

Molarity = 0.499 mole/L

Molality = 0.476 mole/Kg

Normality = 0.998 eq/L

Solution : Given,

Mass of = 49 g

Volume of solution = 1 L

Density of solution = 1.049 g/cc

Molar mass of = 98.079 g/mole

Formula used :

A = Water      B =

For Molarity :    

where,    

= mass of

= Molar mass of

V = volume of solution (in L)

For Molality :    

where,

= Mass of water (in Kg)

For Normality :    Normality = Molarity × Number of ions (Basicity)

Calculation for Molarity :

put all the given values in above formula of Molarity, we get

= 0.499 mole/L

Calculation for Molality :

Volume = 1 L = cc

Mass of water = = Density × Volume = 1.049 g/cc × cc = 1.049 × g = 1.049 Kg

Now put all the given values in above formula of Molality, we get

= 0.476 mole/Kg

Calculation for Normality :

Number of ions (Basicity) in = 2

Now put all the values in above formula of Normality, we get

Normality = 0.499 × 2 = 0.998 eq/L

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