Math, asked by DARKW3B, 1 day ago

49. If in triangles PQR and XYZ,
PQ/XZ=PR/XY=QR/YZ,
then:
(a) ∆PRQ - ∆XZY (b) ∆QRP - AYXZ
(c) ∆PQR - ∆XYZ (d) ∆PQR - ∆XZY​

Answers

Answered by sarasuniradhara447
0

Step-by-step explanation:

Correct option is

B

5:4

given that

ΔPQR ∼ ΔXYZ

PQ=5,QR=4,PR=7

the lengths of the corresponding sides of two similar triangles are proportional.

XY

PQ

=

YZ

QR

=

XZ

PR

XY

5

=

YZ

4

rearranging

4

5

=

YZ

XZ

XZ,YZ are in ratio of 5:4

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