Question

49" If the product of five numbers in GP is 1024, then the middle number is​

Answer 1

Answer:

Let the five numbers in GP be N/r^2, N/r, N, Nr, Nr^2 where N is the middle number and r is the common ratio. Multiplying all pf them, we get, Therefore, N = 4.

Answer 2

Answer:

1 2 4 8 16

1 -2 4 -8 16

Step-by-step explanation:

Find five numbers in G. P. such that their

product is 1024 and fifth term is square of the

third term.

Let say 5 numbers in GP are

a , ar , ar² , ar³ ar⁴

fifth term is square of the third term.

=> ar⁴ = (ar²)²

=> ar⁴ = a²r⁴

=> a = a²

=> 1 = a

five numbers are

1 , r , r² , r³ r⁴

Products of five number of GP

= 1 * r * r² * r³ * r⁴

= r¹⁰

product is 1024

=> r¹⁰ = 1024

=> r = ±2

GP

1 2 4 8 16

1 -2 4 -8 16

Hey!!!! dear it's your answer

Step-by-step explanation:

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