Question

49
In how many years does the sum of 1.200
become 1.800 at the rate of simple interest
of 55 per annum?
(A) 10
(B) 20
(C) 18
(D) 25​

Answer 1

Step-by-step explanation:

$simple \: interest = 1800 - 1200 = 600$

$si = \frac{p \times t \times r}{100} \\ 600 = \frac{1200 \times t \times 55}{100 } \\ 600 = 12 \times t \times 55 \\ 600 = 660 \times t \\ \frac{600}{660} = t \\ \frac{60}{66} = t \\ \frac{10}{11} = t \\ 0.9090 = t$