Question

*49 का वर्गमूल ज्ञात करते समय 1 से प्रारम्भ करते हुए विषम संख्याओं के बार-बार घटाव का उपयोग कर 0 प्राप्त होने तक 'n' चरण बनते हैं। 'n' का मान क्या है?*

1️⃣ 6
2️⃣ 8
3️⃣ 5
4️⃣ 7​

Answer 1

Answer:

answer is :-8

Step-by-step explanation:

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Answer 2

n = 7

Step-by-step explanation:

Now, according to the given information, 49 is the given number and we need to find the number of times that an odd number has to be continuously subtracted from the given number 49 to make it 0, for the process of calculating the square root of the number 49.

Now, 7 is a factor of 49 and subtracting 7 from 49 we get,

49 - 7 = 42

Again, subtracting 7 from 42, we get,

42 - 7 = 35

Again, subtracting 7 from 35, we get,

35 - 7 = 28

Again, subtracting 7 from 28, we get,

28 - 7 = 21

Again, subtracting 7 from 21, we get,

21 - 7 = 14

Again, subtracting 7 from 14, we get,

14 - 7 = 7

Again, subtracting 7 from 7, we get,

7 - 7 = 0.

Thus, 7 has been subtracted from 49 for 7 times to get 0.

Thus, 7 is the value of the square root of 49.

Thus, n = 7.

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