Question

49. One of the factors of the
X^4 - 7x³+ 5x² - 6x + 81 is
(a) x + 2 (b) x - 2 (C) x + 3
(d) x - 3​

Answer 1

Answer:

c is the crrct one

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Answer 2

Answer:

x-3 is. a factor

Step-by-step explanation:

let,

f(x) = x⁴ - 7x³+ 5x² - 6x + 81

g(x) = x + 2 => If g(x)=0 then x=-2

f(-2)=16+56+20-12+81=161 !=0

p(x)= x - 2 => If p(x)=0 then x=2

f(-2)=16-56+20-12+81=49 !=0

t(x)= x +3 => If t(x)=0 then x=-3

f(-3)=81+189+45+18+81=414 !=0

r(x)= x -3 => If r(x)=0 then x=3

f(-3)=81-189+45-18+81=207-207=0

=> (x-3) is a factor of x⁴ - 7x³+ 5x² - 6x + 81