Question

49. The H.C.F. of x2 - 9, x3 - 27 and x2 - 7x + 12
will be:
A. (x2 - 9)
B. (x - 3)2
C. (x + 3)
D. (x - 3)​

Answer 1

Answer:

A. (x2-9)

Step-by-step explanation:

Correct option is A

x−3

(x2−9)=(x−3)(x+3)

(x3−27)=(x3−33)=(x−3)(x2−3x+9)

(x2−8x+15)=(x−3)(x−5)

∴ H.C.F. of (x2−9),(x3−27) and (x2−8x+15) is x−3.

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Answer 2

Answer:

please explain A option