Question

49. The maximum number of electrons that can be
identified with the quantum number l = 2 for Fe3+
ion will be
(1) 3
(2) 4
(4) 6
(3) 5​

Answer 1

Answer:

Fe or iron has 2 isotopes

but the valancy of the Fe3+

is always 3

Answer 2

Answer:

5

Explanation:

The configuration of $Fe^{3+}$ is as follows

The configuration of the Iron electron the first two electrons will travel in 1s orbital. Since s cannot hold only two electrons the next 2 electrons of Iron go into the 2s orbital. The next six electrons will travel in a 2p orbital. The p orbital can hold up to six electrons. We will place six in a 2p orbital and place the next two electrons in the 3s. As 3s when now full we will move to 3p where we will place the next six electrons. We now switch to 4s orbital where we place the remaining two electrons. After the 4s are full we place the remaining five electrons in a 3d orbital and end with $3d^{5}$:

$Fe$: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{6}$

$Fe^{3+}= 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{5}$

Given l=2, signifies d orbital, and thus the maximum number of electrons is 5.

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