Question

49. The quantity of CO, in 500ml of soda water
when packed under 2.5 atm CO, pressure at
298 k is ....... gm (Henry's law constant
1.67 x 108 pa at 298K)
1) 0.64
2) 1.86 3) 6.4 4) 18.6 .........plz anyone say procedure for it.......​

Answer 1

Here x is the mole fraction of carbon dioxide in the carbon dioxide water mixture.

$p </p><p>CO2</p><p> </p><p> =2.5atm=2.5×1.01325×10 </p><p>5</p><p> Pa=2.533125×10 </p><p>5</p><p> Pa$

$x= </p><p>moles of CO </p><p>2</p><p> </p><p> +moles of H </p><p>2</p><p> </p><p> O</p><p>moles of CO </p><p>2</p><p> </p><p> </p><p> </p><p> </p><p>$

$∴x=mole fraction= </p><p>K </p><p>H</p><p> </p><p> </p><p>p </p><p> </p><p> CO </p><p>2</p><p> </p><p> </p><p> </p><p> = </p><p>1.67×10 </p><p>8</p><p> </p><p>2.533125×10 </p><p>5</p><p> </p><p> </p><p> =1.51×10 </p><p>−3$

$</p><p>So, moles of </p><p>27.78</p><p>CO </p><p>2</p><p> </p><p> </p><p> </p><p> =1.51×10 </p><p>−3</p><p> or moles of CO </p><p>2</p><p> </p><p> =0.042moles.$

$Hence the amount of CO </p><p>2</p><p> </p><p> in 500 ml of soda water is 0.042×44=1.86g$