Question

49. The ratio of the energy required to remove an electron
from the first three Bohr's orbits of hydrogen is
(1) 3:2:1
(2) 9:4:1
(3) 36: 9:4
(4) 1:4:9​

Answer 1

Answer:

36:9:4

Explanation:

e= -13.6z2/n2

E1:E2:E3=1/1:1/4:1/9

multiply by 36

=36/1:36/4:36/9

=36:9:4