Question

49^(x+1)7^(2x)=350 please help me​

Answer 1

Step-by-step explanation:

49x+1+7^2x=350

We move all terms to the left:

49x+1+7^2x-(350)=0

We add all the numbers together, and all the variables

49x+7^2x-349=0

We move all terms containing x to the left, all other terms to the right

49x+7^2x=349

Answer 2

Step-by-step explanation:

log 7^x = log 49

x log 7 = log 49 (because you can move the x exponent to the front of log 7).

x = log 49/ log 7

Plug that into a calculator.

x = 2…

Or you can do this:

x =(log 7/ log 7) + (log 7/ log 7)

x = 1 + 1; x = 2….

However, if you did that, you'd know that 7^2 = 49 off the top of your head, and it would thus save time.