Question

(49)^x+4 = 7^2 *(343)^x+1​

Answer 1

$Given \: (49)^{x+4} = 7^{2} \times (343)^{x+1}$

$\implies (7^{2})^{x+4} = 7^{2} \times (7^{3})^{x+1}$

$\implies 7^{2(x+4)} = 7^{2} \times 7^{3(x+1)}$

$\implies 7^{2x+8} = 7^{2} \times 7^{3x+3}$

$\implies 7^{2x+8} = 7^{2+3x+3}$

$\implies 2x + 8 = 2+3x+3$

$\implies 2x + 8 = 3x+5$

$\implies 8 - 5 = 3x - 2x$

$\implies 3 = x$

Therefore.,

$\red{ Value \: x } \green { = 3}$

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