491. If A = 1 + 2P and B = 1 + 2-P
then what is the value of B?
(a) (A+1)/(A-1) (b) (A+2)/(A+1)
(c) A/(A-1) (d) (A-2)/(A+1)
Answers
Answered by
0
Answer:
Option c is the right answer for this question
Answered by
0
Answer:
Going by options:
(a) Minimum value of P(A∩B) is the higher of P(A) and P(B) i.e.
3
2
and maximum value is 1. So, (a) is true.
(b) Maximum intersection of P(A∩
B
ˉ
) is the minimum of P(A) and P(
B
ˉ
) i.e. minimum of
2
1
and
3
1
=
3
1
. So, (b) is true.
(c) P(A)+P(B)=
2
1
+
3
2
=
6
7
. Hence, P(A∩B)≥
6
7
−1=
6
1
.
Again, maximum intersection of P(A∩B) is the minimum of P(A) and P(B) i.e. minimum of
2
1
and
3
2
=
2
1
. So, (c) is true.
(d) Maximum intersection of P(B∩
A
ˉ
) is the minimum of P(B) and P(
A
ˉ
) i.e. minimum of
3
2
and
2
1
=
2
1
.
Again, P(
A
ˉ
)+P(B)=
2
1
+
3
2
=
6
7
. Hence, P(
A
ˉ
∩B)≥
6
7
−1=
6
1
. So, (d) is true.
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