492
Math, 10
Thus, area of circle is 134 m
The radius of a semicircular plotis 31
m. Ynd its area and perimeter
Solution : Givea :
Radius of semi-circular plor
Thus, radhus or wheel - 14om
The area ofa ctroular plates
Find its circumfernede
Solution : Given : Area orchewa
Area
520
122121
Let radhus of plate is rom, then
?
and
perimeter
21221
66 +42
= 108 m
Thus, area of plotis 603 m and perimeteris1os
Circumference of circular plate-2
Thus, circumference of circular plate
0. * The wheel of scooter covered 88 m
distance in 100 revolution. Find the radius of
wheel.
Solution : Given:
In 100 revolutions, wheel covered a distance
of 88 m.
Distance covered by wheel in 1 rotation
circumference of wheel
Distance covered
Number of Revolution
0.6. The circumference of circle
perimeter of a square If area of square
sq m, then find the area of circle
Solution : Ler side of squarem
then perimeter of square
and
area of square me
According to question
Area of square - 4
88
100 m
Let radius of wheel is x, then
88
2
100
Perimeter of square
**
► 2xx8
88x7
* 2x 22 x 100 m
Let radius of circle is
circumference of circle-periner
2x 88
Answers
Answer:
Math, 10
Thus, area of circle is 134 m
The radius of a semicircular plotis 31
m. Ynd its area and perimeter
Solution : Givea :
Radius of semi-circular plor
Thus, radhus or wheel - 14om
The area ofa ctroular plates
Find its circumfernede
Solution : Given : Area orchewa
Area
520
122121
Let radhus of plate is rom, then
?
and
perimeter
21221
66 +42
= 108 m
Thus, area of plotis 603 m and perimeteris1os
Circumference of circular plate-2
Thus, circumference of circular plate
0. * The wheel of scooter covered 88 m
distance in 100 revolution. Find the radius of
wheel.
Solution : Given:
In 100 revolutions, wheel covered a distance
of 88 m.
Distance covered by wheel in 1 rotation
circumference of wheel
Distance covered
Number of Revolution
0.6. The circumference of circle
perimeter of a square If area of square
sq m, then find the area of circle
Solution : Ler side of squarem
then perimeter of square
and
area of square me
According to question
Area of square - 4
88
100 m
Let radius of wheel is x, then
88
2
100
Perimeter of square
**
► 2xx8
88x7
* 2x 22 x 100 m
Let radius of circle is
circumference of circle-periner
2x 88
Answer:
Answer:
Math, 10
Thus, area of circle is 134 m
The radius of a semicircular plotis 31
m. Ynd its area and perimeter
Solution : Givea :
Radius of semi-circular plor
Thus, radhus or wheel - 14om
The area ofa ctroular plates
Find its circumfernede
Solution : Given : Area orchewa
Area
520
122121
Let radhus of plate is rom, then
?
and
perimeter
21221
66 +42
= 108 m
Thus, area of plotis 603 m and perimeteris1os
Circumference of circular plate-2
Thus, circumference of circular plate
0. * The wheel of scooter covered 88 m
distance in 100 revolution. Find the radius of
wheel.
Solution : Given:
In 100 revolutions, wheel covered a distance
of 88 m.
Distance covered by wheel in 1 rotation
circumference of wheel
Distance covered
Number of Revolution
0.6. The circumference of circle
perimeter of a square If area of square
sq m, then find the area of circle
Solution : Ler side of squarem
then perimeter of square
and
area of square me
According to question
Area of square - 4
88
100 m
Let radius of wheel is x, then
88
2
100
Perimeter of square
**
► 2xx8
88x7
* 2x 22 x 100 m
Let radius of circle is
circumference of circle-periner
2x 88