Question

492
Math, 10
Thus, area of circle is 134 m
The radius of a semicircular plotis 31
m. Ynd its area and perimeter
Solution : Givea :
Radius of semi-circular plor
Thus, radhus or wheel - 14om
The area ofa ctroular plates
Find its circumfernede
Solution : Given : Area orchewa
Area
520
122121
Let radhus of plate is rom, then
?
and
perimeter
21221
66 +42
= 108 m
Thus, area of plotis 603 m and perimeteris1os
Circumference of circular plate-2
Thus, circumference of circular plate
0. * The wheel of scooter covered 88 m
distance in 100 revolution. Find the radius of
wheel.
Solution : Given:
In 100 revolutions, wheel covered a distance
of 88 m.
Distance covered by wheel in 1 rotation
circumference of wheel
Distance covered
Number of Revolution
0.6. The circumference of circle
perimeter of a square If area of square
sq m, then find the area of circle
Solution : Ler side of squarem
then perimeter of square
and
area of square me
According to question
Area of square - 4
88
100 m
Let radius of wheel is x, then
88
2
100
Perimeter of square
**
► 2xx8
88x7
* 2x 22 x 100 m
Let radius of circle is
circumference of circle-periner
2x 88​

Answer 1

Answer:

Math, 10

Thus, area of circle is 134 m

The radius of a semicircular plotis 31

m. Ynd its area and perimeter

Solution : Givea :

Radius of semi-circular plor

Thus, radhus or wheel - 14om

The area ofa ctroular plates

Find its circumfernede

Solution : Given : Area orchewa

Area

520

122121

Let radhus of plate is rom, then

?

and

perimeter

21221

66 +42

= 108 m

Thus, area of plotis 603 m and perimeteris1os

Circumference of circular plate-2

Thus, circumference of circular plate

0. * The wheel of scooter covered 88 m

distance in 100 revolution. Find the radius of

wheel.

Solution : Given:

In 100 revolutions, wheel covered a distance

of 88 m.

Distance covered by wheel in 1 rotation

circumference of wheel

Distance covered

Number of Revolution

0.6. The circumference of circle

perimeter of a square If area of square

sq m, then find the area of circle

Solution : Ler side of squarem

then perimeter of square

and

area of square me

According to question

Area of square - 4

88

100 m

Let radius of wheel is x, then

88

2

100

Perimeter of square

**

► 2xx8

88x7

* 2x 22 x 100 m

Let radius of circle is

circumference of circle-periner

2x 88

Answer 2

Answer:

Answer:

Math, 10

Thus, area of circle is 134 m

The radius of a semicircular plotis 31

m. Ynd its area and perimeter

Solution : Givea :

Radius of semi-circular plor

Thus, radhus or wheel - 14om

The area ofa ctroular plates

Find its circumfernede

Solution : Given : Area orchewa

Area

520

122121

Let radhus of plate is rom, then

?

and

perimeter

21221

66 +42

= 108 m

Thus, area of plotis 603 m and perimeteris1os

Circumference of circular plate-2

Thus, circumference of circular plate

0. * The wheel of scooter covered 88 m

distance in 100 revolution. Find the radius of

wheel.

Solution : Given:

In 100 revolutions, wheel covered a distance

of 88 m.

Distance covered by wheel in 1 rotation

circumference of wheel

Distance covered

Number of Revolution

0.6. The circumference of circle

perimeter of a square If area of square

sq m, then find the area of circle

Solution : Ler side of squarem

then perimeter of square

and

area of square me

According to question

Area of square - 4

88

100 m

Let radius of wheel is x, then

88

2

100

Perimeter of square

**

► 2xx8

88x7

* 2x 22 x 100 m

Let radius of circle is

circumference of circle-periner

2x 88