49a2+140ab+100b2
factorisation
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Answer:
49a²+140ab+100b².
(7a)²+2(7a)(10b)+(10b)².
It is in the form of a²+2ab+b²=(a+b)² where a=7a & b=10b.
(7a)²+2(7a)(10b)+(10b)²=(7a+10b)².
I think this is your answer.
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