Question

49g of Pottasium Chlorate (KClO3) is heated strongly.Calculate the amount of the solid and the gaseous product formed during the reaction.(K=39,Cl=35.5,O=16)

Answer 1

Explanation:

2KClO3 ->2 KCl + 3O2

Moles of KClO3 =

Given mass/ molar mass

49/(31+35.5+48)

49/114.5 = 0.43 moles

moles of kclo3 = moles of kcl formed

= 0.43

Weight of kcl -> 0.43*66.5=28.5g

Weight of O2= 1.5 * 0.43 * 32

[1.5 because 2 reacts with 3, 1 will react with 1.5]

=20.64g