Question

49q^4-4 factorise completely​

Answer 1

$\:\: \underline{\underline{\bf{\large\mathfrak{~~Solution~~}}}}$

$= 49q {}^{4} - 4 \\ = (7q {}^{2} ) {}^{2} - 2 {}^{2} \\ = (7q {}^{2} - 2)(7q {}^{2} + 2)$

Answer 2

Answer:

(√7q-√2)(√7q+√2)(7q²+2)

Step-by-step explanation:

we have,

49q⁴-4

(7q²)²-2²

applying a²-b² = (a-b)(a+b)

(7q²-2)(7q²+2)

[(√7q)²-(√2)²][7q²+2]

(√7q-√2)(7q+√2)(7q²+2) ....ans.