Question

49x^2+2xz+1/49z^2 factorise the following. please urgent

Answer 1

|| 49 x^2 + 2x z + ( 1 / 49 z^2

= (7 x )^2 + 2 ( 7x ) ( 1 / 7 z ) + ( 1 / 7 z )^2

use identity :

a^ 2 + 2ab + b^2 ) = ( a + b )^2

= 7x + 1/ 7 z ) ^2

= ( 7x + z / 7 )^2

= ( 7x + z / 7 ) ( 7x + z / 7 )

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| : | hope it helps | : |
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Answer 2

$49 {x}^{2} + 2xz + \frac{1}{49} {z}^{2} \\ \\ = {(7x)}^{2} + 2 \times 7x \times \frac{z}{7} + {( \frac{z}{7} )}^{2}$   $\text{It is in the form of (a^2 + 2ab + b^2 ) } \\ \text{which is the expansion of (a+b)^2 }$   ${(7x)}^{2} + 2 \times 7x \times \frac{z}{7} + {( \frac{z}{7} )}^{2} \\ \\ ={ (7x + \frac{z}{7} )}^{2} \\ \\ =(7x + \frac{z}{7} )(7x + \frac{z}{7} )$