Question

49x+3y+12=0
18x+6y+24=0​

Answer 1

Given :

• 49x + 3y + 12 = 0
• 18x + 6y + 24 = 0

To Find :

• Value of x = ?
• Value of y = ?

Solution :

• 49x + 3y + 12 = 0 - (i)
• 18x + 6y + 24 = 0 - (ii)

From equation (i) :

$\sf : \implies 49x + 3y + 12 = 0$

$\sf : \implies 49x + 3y = - 12$

$\sf : \implies 49x = - 12 - 3y$

$\sf : \implies x = \dfrac{-12-3y}{49}$

Substitute in equation (ii) :

$\sf : \implies 18\times \Bigg(\dfrac{-12-3y}{49}\Bigg) + 6y + 24 = 0$

$\sf : \implies dfrac{-216-54y}{49} + 6y + 24 = 0$

$\sf : \implies dfrac{-216-54y+ 294y +1176}{49} = 0$

$\sf : \implies -216-54y+ 294y +1176 = 0$

$\sf : \implies 240y+ 960 = 0$

$\sf : \implies 240y = -960$

$\sf : \implies y = \cancel{\dfrac{-960}{240}}$

$\sf : \implies y = -4$

Hence, value of y = - 4.

Substitute in equation (i) :

$\sf : \implies 49x + 3\times (-4) + 12 = 0$

$\sf : \implies 49x - 12 + 12 = 0$

$\sf : \implies 49x + 0 = 0$

$\sf : \implies 49x = 0$

$\sf : \implies x = 0$

Hence, value of x = 0.

So, Answer is :

• x = 0
• y = - 4