49x2 - y2
Factorise using suitable identity :
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Here 49x2−112xy+64y2, we see that
49x2=(7x)2,64y2=(8y)2 and 112xy=2(7x)(8y)
Thus comparing with Identity II,
(x−y)2≡x2−2xy+y2, we get
49x2−112xy+64y2=(7x)2−2(7x)(8y)+(8y)2
=(7x−8y)2
=(7x−8y)(7x−8y)
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