Math, asked by rahmanbushra, 3 months ago

4a^2+1/4a^2-2+4a-1/a​

Answers

Answered by mahababu29
5

Answer:

here is your answer mate

Step-by-step explanation:

(4 a^2 + 1/4a^2 - 2)+ 4a -1/a

{ (2a)^2 + 1/(2a) ^2 - 2} + 4a - 1/a

using identity 2 : (a -b ) ^2

( 2a - 1/2a ) ^2 +4a - 1/a

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