Question

4a^2+12ab+9b^2-8a-12b



ANSWER IT....

Answer 1

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.(2a)^2+2×2a×3b+(3b)^2-4(2a+3b)

.(2a+3b)^2-4(2a+3b)=(2a+3b)(2a+3b-4)

Answer 2

Step-by-step explanation:

The given equation is:

4a^{2}+12ab+9b^{2}-8a-12b4a

2

+12ab+9b

2

−8a−12b

Rewriting the terms and taking 12ab as 6ab+6ab, we get

4a^{2}-8a+6ab+6ab+9b^{2}-12b4a

2

−8a+6ab+6ab+9b

2

−12b

Taking 2a common from first three terms and 3b common from last three terms of the above equation,

2a(2a-4+3b)+3b(2a+3b-4)2a(2a−4+3b)+3b(2a+3b−4)

(2a+3b)(2a-4+3b)(2a+3b)(2a−4+3b) which is the required solution.