4a^2 + 12ab + 9b^2 : factories it.
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4a^2 +12ab+9b^2
Multiplying last and first position
We get
4a×9b=36a^2b^2
Now we have to find such two numbers such that their sum is 12ab and product 36a^2b^2
So
4a^2 +6ab +6ab +9 b^2
2a(2a +3b) +3b(2a+3b)
(2a+3b)(2a+3b)
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