Question

(4a^2 - 64 ) ÷ ( 2a + 8) PLS FRND... SHOW RHE COPY WORK....​

Answer 1

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(4a^2 - 64 ) ÷ ( 2a + 8)

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$\dfrac{4 {a}^{2} - 64 }{2a + 8} \\ \\ \\ = \dfrac{( {2a)}^{2} - {(8)}^{2} }{2a + 8} \\ \\ \\ = \dfrac{(2a - 8)(2a + 8)}{(2a + 8)} \: \: \: \\ \\(as \: {a}^{2} - {b}^{2} = (a + b)(a - b)) \\ \\ \\ = 2a - 8$

$\bold\purple{ADDITIONAL\: INFORMATION}$

• a²+b²+2ab=(a+b)²

• a²+b²-2ab=(a-b)²

• a²-b²=(a+b)(a-b)

• a³+b³=(a+b)(a²+b²-ab)

• a³-b³=(a-b)(a²+b²+ab)

• a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

• a³+b³+3ab(a+b)=(a+b)³

• a³-b³-3ab(a-b)=(a-b)³