Question

4a^2+b^2+4a+8a+4b-4​

Answer 1

Solution:

/* We know the algebraic identity:

x²+y²+z²+2xy+2yz+2zx

= (x+y+z)² */

Here, it is given that

4a²+b²+4a+8a+4b-4

= 4a²+b²-4+4a+8a+4b

=(2a)²+b²+(-2)²+2*(2a)*b+2*b*(-2)+2*(-2)*(2a)

= (2a+b-2)²

= (2a+b-2)(2a+b-2)

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