Question

4a^2+b^2+4ab+8ab+4b+4 factorise​

Answer 1

Answer:

Answer:

/* We know the algebraic identity:

x²+y²+z²+2xy+2yz+2zx = (x+y+z)². */

Now ,

4a²+b²+4ab+8a+4b+4

= 4a²+b²+4+4ab+4b+8a

=(2a)²+b²+2²+2*2a*b+2*b*2+2*2*2a

= (2a+b+2)²

= (2a+b+2)(2a+b+2)

•••••

Answer 2

$4 {a}^{2} + {b}^{2} + 4ab + 8ab + 4b + 4 \\ \\ = >4 {a}^{2} + {b}^{2} + 12ab + 4b + 4$