Question

4a^2+b^2+c^2=2(2a-3+2b-c) then the value of 4a-b-3c

Answer 1

or,(2a)^2+b^2+c^2-4a-4b+2c=-6
or,(2a)^2-4a+1+c^2+2c+1+b^2-4b+4=0
or,(2a-1)^2+(b-2)^2+(c+1)^2=0
or,2a-1=0
a=1/2
b-2=0
b=2
c+1=0
c=-1
4a-b-3c=2-2+3=3