Question

4a^2+b^2+c^2-4ab+2bc-4ca using identity

Answer 1

this is the answer use the identity
$a {}^{2} + b {}^{2} + c {}^{2} + 2ab + 2bc + 2ca. \: since \: - 4ab \: and - 4ca \: is \: negative \: we \: have \: to \: take \: a \: also \: as \: negative$

Answer 2

Answer:

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