Question

(4a-2b-3c)2
pls answer my question
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Answer 1

Answer:

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The given expression (4a−2b−3c) 2 can be solved as shown below:

(4a−2b−3c) 2

=(4a) 2 +(−2b) 2 +(−3c) 2 +(2×4a×(−2b)+(2×(−2b)×(−3c+(2×(−3c)×4a)

(∵(a+b+c) 2 =a 2+b2+c 2 +2ab+2bc+2ca)

=16a 2 +4b 2+9c 2 −16ab+12bc−24ca

Hence, (4a−2b−3c) 2

=16a 2+4b 2+9c 2−16ab+12bc−24ca.

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