Question

(4a-3) ³ - (4a+3) ³ simply​

Answer 1

Solution:

Let (4a-3) be a

and

(4a+3) be b

then

a³-b³ = (a-b) (a²+b²+ab)

(4a-3)³ - (4a+3)³

step 1 = [(4a-3) - (4a+3) [(4a-3)² + (4a+3)²+(4a-3) (4a+3)]

step 2 = [4a-3-4a-3] [(16a²+9) + (16a²+9) + (16a²+12a-12a-9)]

step 3 = [-6] [16a²+9+16a²+9+16a²+12a-12a-9]

step 4 = [-6] [48a²+9]

step 5 = (-288a²-54)