Question

4a^3-9a^2+3a+2 factorisation
​

Answer 1

Answer:

first put -1 to 1 no. if ans. come zero then that is factor

a =1 then ans. zero so,

a-1 is factor of this eq.

now divide eqn. by a-1

a-1÷4a^3-9a^2+3a+2=

4a^2-5a-2

now factorise this eqn. by quadratic formula so u can find factor

thanks for this question

Answer 2

Factor 4a3−9a2+3a+2

4a3−9a2+3a+2

=(a−1)(4a2−5a−2)