Math, asked by HarshitBuddy, 24 days ago

4a^-3 b^0/2a^2 b^-1

Attachments:

Answers

Answered by sarthak9b
7

Answer:

2b/a^5

Step-by-step explanation:

(4a^-3-2b^0+1)÷2

4a^-5×b/2

2b/a^5

Answered by 123UDAY123
2

Answer:

we know that any variable or constant with power ⁰ is 0

and one with power of 1 or - 1 is no. itself

therefore,

4a‐³×b⁰/2a²×b‐¹

4a‐³×0/2a²× – 1

0/2a² - 1

and we also know that if in a rational no.p/q where

q is not equal to 0 and p is equal to 0 there

p/q = 0

Hence

4a-³b⁰/2a²b‐¹ = 0

Similar questions