Question

(4a - 3b + 11c) (a+b) - (16b - 13c + 2a) (a- c)


please ans and send me the method
only ans otherwise ans will reported​

Answer 1

$(4a - 3b + 11c) (a+b) - (16b - 13c + 2a) (a- c) \\ \\ a(4a - 3b + 11c) + b(4a - 3b + 11c) - a(16b - 13c + 2a) - c(16b - 13c + 2a) \\ \\ {4a}^{2} - 3ab + 11ac + 4ab - {3b}^{2} + 11bc - 16ab + 13ac - {2a}^{2} - 16bc + {13c}^{2} - 2ac \\ \\ {4a}^{2} - {2a}^{2} - {3b}^{2} + {13c}^{2} - 3ab + 4ab - 16ab +11bc - 16bc + 11ac + 13ac - 2ac \\ \\ {2a}^{2} - {3b }^{2} + {13c}^{2} - 15ab - 5bc + 22ac.$

Answer 2

Answer:

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