Question

(4a+3b)³ use suitable identitity and solve​

Answer 1

Answer:

It can be expanded as: $64a^3+27b^3+144a^2b+108ab^2$

Step-by-step explanation:

We know the identity: $(x+y)^3=x^3+y^3+3xy(x+y)$

Hence, according to the question,

$x=4a\\y=3b$

Substituting these values in the above identity,

$(4a+3b)^3=(4a)^3+(3b)^3+3(12ab)(4a+3b)$

$=64a^3+27b^3+36ab(4a+3b)$

$=64a^3+27b^3+(36ab*4a)+(36ab*3b)$

$=64a^3+27b^3+144a^2b+108ab^2$

Hope it helps.

Answer 2

Answer:

16a³ + 9b³ + 144a²b + 108ab²

Step-by-step explanation:

use identity (a+b)³ = a³ + b³ + 3ab(a+b)

here ,   a = 4a  , b = 3b

(4a +3b)³ = (4a)³ + (3b)³ + 3(4a x 3b)(4a + 3b)

             = 16a³ + 9b³ + 36ab(4a+3b)

(4a +3b)³ = 16a³ + 9b³ + 144a²b + 108ab²

hope it helps!