Question

4a-3b-32=0,a+b=1 simultaneously

Answer 1

4a-3b-32=0
4a-3b=32 -------- 1
a+b=1 -–––––––2
multiply by 3 in eqn. 2 and then adding eqn. 1 and 2
4a-3b=32
3a+3b=3

7a=35
a=35/7
a=5
put the calue of a in eqn. 2
a+b=1
5+b=1
b=1-5
b= -4

a=5
b= -4

Answer 2

a=4,b=-3,c=-32
sum of roots =-b/a
-b/a=1
-(-3)/4=1
3/4=1
3=4