Math, asked by VijuB002, 1 year ago


(4a-3b)(4a-3b)=
(4z+5e)(4z-5e)=
(2a+3p)(2a+3p)=
(3p-9r)(3p-9r)=
(20a+5d)(20a-5d)=

Answers

Answered by samyak03
0
⏩Hey mate... Here is your answer...!!!⏪

⏩(4a-3b)(4a-3b)=16a²-24ab+9b²⏪
⏩(4z+5e)(4z-5e)=16z²-25e²⏪
⏩(2a+3p)(2a+3p)=4a²+12ap+9p²⏪
⏩(3p-9r)(3p-9r)=9p²-54pr+81r²⏪
⏩(20a+5d)(20a-5d)=400a²-25d²⏪

⏩Hope this will help you...!!!⏪

VijuB002: beacause I have got 4x2 + 64xy + 16y
samyak03: no buddy it's wrong
samyak03: its simple
VijuB002: explain please
samyak03: kal explain kru to chlega???
VijuB002: what
samyak03: nothing
samyak03: just use distributive property
samyak03: hey r u there?
VijuB002: hey sorry you were right
Answered by tulikas1407
0

Answer:

1. 4a^{2} - 3b^{2}

2. 4z^{2} - 5e^{2}

3. 2a^{2} - 3p^{2}

4. 3p^{2} - 9r^{2}

5. 20a^{2} - 5d^{2}

Step-by-step explanation:



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