Question

( 4a + 9 )³ Expand it​

Answer 1

$(A+B)^3= a^3+ b^3 +3ab(a+b)\\Here A= 4a, B=9\\(4a+9)^3= (4a)^3+(9)^3 +3*4a*9(4a+9)\\\\= 64a^3+729+ 108a(4a+9)\\= 64a^3+729+ 432a^2+972a\\= 64a^3+432a^2+972a+729$

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