Question

4a -b +2c²
Please factorise this equation

Answer 1

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we have

(4a -b +2c)²

= (4a)² + (-b)² + (2c)² + 2(4a)(-b) + 2(-b)(2c)+2)2c)(4a)

[∵ a² + b² + c² + 2ab + 2bc + 2ca = (a + b + c)²

= 16a² + b² + 4c² - 8ab - 4ac + 16ca