Question

(4a-b)³-(4a+3)³ ,please answer
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Answer 1

Answer:

a = 0

b = - 3

Step-by-step explanation:

(4a - b)³ - (4a + 3)³ = 0

Applying the formula of a³- b³ = (a - b)(a² + ab + b²) and a³ + b³ = (a + b)(a² - ab + b²)

(4a - b)(16a² + 4ab + b²) - (4a + 3)(16a² - 12a + 9) = 0

(4a - b)(4a + b)² - (4a + 3)(4a - 3)² = 0

(4a - b)(4a + b)(4a + b) - (4a + 3)(4a - 3)(4a - 3) = 0

(4a + b) - (4a - 3) = 0 ---- 1

4a + b - 4a + 3 = 0

b + 3 = 0

b = - 3

Putting value of b in 1

(4a + b) - (4a - 3) = 0

4a + (- 3) - 4a - 3 = 0

4a - 3 = 4a + 3

4a - 4a = 3 + 3

0a = 6

a = 0

Hope it helps you....