Question

4a cube -8a square+3a-6 factorise​

Answer 1

Answer:

Hii chhavi

Here is ur ans.

$\sf \: 4 {a}^{3} - 8 {a}^{2} + 3a - 6$

First check at which no this term become 0

When we put a=2 it become 0 hence

(a-2) is a factor

Now write (a-2) three times

$\sf \: = 4 {a}^{2} (a - 2) + 3(a - 2) + 0(a - 2)$

$\sf \: (a - 2)(4 {a}^{2} + 3)$

Required ans