Question

4A long wire is cut into 2 pieces 2:5 ratio of its lengths . what is the ratio of their resistances

Answer 1

Answer:

$R_{1}$ : $R_{2}$ = 2 : 5

Explanation:

Lets consider the ideal resistance as :

R = δ l / A

R ∝ l

$\frac{R_{1} }{R_{2} } = \frac{l_{1} }{l_{2} }$

    = 2/5

$R_{1}$ : $R_{2}$ = 2 : 5

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Answer 2

Answer:

Let the length of the wire be 'l' and area of cross-section be 'A' and resistivity of the material be q

Therefore R =

A

ql

When it is cut then take each of the piece:-

Its resistance =

2A

ql

=

2

R

When joined in parallel Net resistance =

4

R