Question

4a square+4ab+2b square

Answer 1

$4 {a}^{2} + 4ab + 2 {b}^{2} \\ ( {2a)}^{2} + 2(2ab) + ( { \sqrt{2}b })^{2} \\ {(2a + \sqrt{2}b) }^{2}$

Answer 2

HERE IS YOUR ANSWER MATE......;

$= > 4a {}^{2} + 4ab + 2b$

$= > 4a(a + b) + 2b$

$(a + b)(4a + 2b)$

$a = - b$

$a = \frac{ - 2b}{4}$

HOPE IT'S HELPFUL....:-)