Question

4a square- 9(b+c). ​

Answer 1

$4 {a}^{2} - 9(b + c)$

$= (2a) ^{2} - (3) ^{2} ( b + c)$

$using \: a^{2} - {b}^{2} = (a + b)(a - b)$

$= (2a + 3)(2a - 3)(b + c)$

$Hope it helps$