Question

4A square + b square + 4 AB + 8a+ 4 b + 4 factorise it​

Answer 1

Answer:

Group the terms as follows:

4a² + (4ab + 8a) + (b² + 4b + 4)

Factor each part separately:

(2a)² + 4a(b + 2) + (b + 2)²

Let u = 2a

Let v = b + 2

So you have:

u² + 2uv + v²

That's in the form of a perfect square:

(u + v)²

Answer:

(2a + b+2)²

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